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vipsmile666
@vipsmile666
August 2022
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2 задачи по физике. Нужно нормально расписать и каждой задаче график или рисунок, в зависимости от условия
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Verified answer
2.5
mgh=mgL*(1-cos(alpha))=mv^2/2
h=L*(1-cos(alpha))=5*(1-cos(pi/3))=
2,5
м
mgL*(1-cos(alpha))=mv^2/2
v^2=2gL*(1-cos(alpha))
ma=mv^2/L=F-mg
F=m(v^2/L+g)=m(2gL*(1-cos(alpha))/L+g)=mg(3-2cos(alpha))=100*9,8*(3-2*cos(pi/3)) Н =
1960
Н
2.6
m1v1+m2v2=(m1+m2)*u
v2=((m1+m2)*u-m1v1)/m2=u+m1(u-v1)/m2=0,24+20*(0,24-0,3)/30 м/с=
0,2
м/с
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Answers & Comments
Verified answer
2.5mgh=mgL*(1-cos(alpha))=mv^2/2
h=L*(1-cos(alpha))=5*(1-cos(pi/3))=2,5 м
mgL*(1-cos(alpha))=mv^2/2
v^2=2gL*(1-cos(alpha))
ma=mv^2/L=F-mg
F=m(v^2/L+g)=m(2gL*(1-cos(alpha))/L+g)=mg(3-2cos(alpha))=100*9,8*(3-2*cos(pi/3)) Н =1960 Н
2.6
m1v1+m2v2=(m1+m2)*u
v2=((m1+m2)*u-m1v1)/m2=u+m1(u-v1)/m2=0,24+20*(0,24-0,3)/30 м/с=0,2м/с