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vipsmile666
@vipsmile666
July 2022
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2 задачи по физике. пожалуйста
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1)
h=v0*t+at^2/2
8=4t-t^2/2
t^2-8t+16=0
t=4 сек
A=F*h
ma=F-mg
F=m(g+a)=A/h
m=A/h*1/(g+a)=35000/8*1/(9,8-1) =
497,1591
кг ~ 497 кг
N=A/t=35000/4 Вт =
8750
Вт = 8,75 кВт
2)
F*S=mg*мю*S=mv^2/2
v=корень(2*g*S*мю) = корень(2*10*4,5*0,1) = 3 м/с
mgh = mv^2/2+Fтр*L
Fтр=mg*cos(alpha)*мю
L=h/sin(alpha)
mgh = mv^2/2+Fтр*L
mgh = mv^2/2+mg*cos(alpha)*мю*h/sin(alpha)
gh = v^2/2+gh*мю/tg(alpha)
tg(alpha)=мю/(1-v^2/(2gh)) = 0,1/(1-3^2/(2*10*0,5)) = 1
alpha = 45 град
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Answers & Comments
Verified answer
1)h=v0*t+at^2/2
8=4t-t^2/2
t^2-8t+16=0
t=4 сек
A=F*h
ma=F-mg
F=m(g+a)=A/h
m=A/h*1/(g+a)=35000/8*1/(9,8-1) =497,1591 кг ~ 497 кг
N=A/t=35000/4 Вт = 8750Вт = 8,75 кВт
2)
F*S=mg*мю*S=mv^2/2
v=корень(2*g*S*мю) = корень(2*10*4,5*0,1) = 3 м/с
mgh = mv^2/2+Fтр*L
Fтр=mg*cos(alpha)*мю
L=h/sin(alpha)
mgh = mv^2/2+Fтр*L
mgh = mv^2/2+mg*cos(alpha)*мю*h/sin(alpha)
gh = v^2/2+gh*мю/tg(alpha)
tg(alpha)=мю/(1-v^2/(2gh)) = 0,1/(1-3^2/(2*10*0,5)) = 1
alpha = 45 град