х 0,025моль
Ag2O+CH3COH=>2Ag+CH3COH
n(Ag)=m/M=2,7/108=0,025моль
х=0,025×1/2=0,0125моль
m(CH3COH)=n×M=0,0125×(12+3+12+16+1)=0,925г
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х 0,025моль
Ag2O+CH3COH=>2Ag+CH3COH
n(Ag)=m/M=2,7/108=0,025моль
х=0,025×1/2=0,0125моль
m(CH3COH)=n×M=0,0125×(12+3+12+16+1)=0,925г