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111МоРкОвКа111
@111МоРкОвКа111
July 2022
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y=14√2sinx-14x+3.5п+3
найти наибольшее значение функции на (0;π/2)
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goroshynka
Y'(x)=14√2*cos x-14
14√2*cos x-14=0
14√2cos x=14
√2cos x=1
cos x=1/√2
x=+-pi/4+2pi*n
на данном интервале x=pi/4
y(pi/4)=14√2*sin pi/4-14*pi/4+3,5pi+3=14*√2*√2/2-3,5pi+3,5pi+3=14+3=17
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Answers & Comments
14√2*cos x-14=0
14√2cos x=14
√2cos x=1
cos x=1/√2
x=+-pi/4+2pi*n
на данном интервале x=pi/4
y(pi/4)=14√2*sin pi/4-14*pi/4+3,5pi+3=14*√2*√2/2-3,5pi+3,5pi+3=14+3=17