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thomasscrazy
@thomasscrazy
July 2022
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Найдите корень уравнения Cos (π(x-1))/3 = 1/2
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Cos (π(x-1))/3 = 1/2
1)
(π(x-1))/3=arccos(1/2)+2πn, (π(x-1))/3=π/3+2πn, x=2+2n, n∈Z,
2) (π(x-1))/3=-arccos(1/2)+2πn, (π(x-1))/3=-π/3+2πn x=2n, n∈Z,
x=2n, n∈Z,
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Cos (π(x-1))/3 = 1/21) (π(x-1))/3=arccos(1/2)+2πn, (π(x-1))/3=π/3+2πn, x=2+2n, n∈Z,
2) (π(x-1))/3=-arccos(1/2)+2πn, (π(x-1))/3=-π/3+2πn x=2n, n∈Z,
x=2n, n∈Z,