Объяснение:
arcsin(1/√2)+arccos(1/2)+arcctg√3=
arcsin(√2/2)+π/3+π/6=π/4+π/3+π/6=
=(3π+4π+2π)/12=9π/12=3π/4
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Verified answer
Объяснение:
arcsin(1/√2)+arccos(1/2)+arcctg√3=
arcsin(√2/2)+π/3+π/6=π/4+π/3+π/6=
=(3π+4π+2π)/12=9π/12=3π/4