Срочно! Докажите тотжество:
4cos(π/6+α)*cos(π/6-α)=1-4sin^2α
вроде по формуле: cos(α)*cos(β)=1/2[cos(α+β)+cos(α-β)]
4cos(π/6+α)*cos(π/6-α)=1-4sin^2α
вроде по формуле: cos(α)*cos(β)=1/2[cos(α+β)+cos(α-β)]
More Questions From This User See All