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novokuznetsk
@novokuznetsk
August 2022
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Решить интеграл посредством замены. Но как? dy/(1-y^2) Если делать как u = 1-y^2, du = -2ydy, а дальше идет бред в виде -du/2y = dy. ПОМОГИТЕ
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moboqe
∫1/(1-y^2)dy= -∫1/(y^2-1)=1/2ln|(y-1)/(y+1)|+C
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