Ответ:
17/81
Объяснение:
cos4∝=cos²2∝-sin²2∝
cos2∝=cos²∝-sin²∝
sin2∝=2cos∝*sin∝
cos4∝=cos²2∝-sin²2∝=(cos²∝-sin²∝)²-4cos²∝*sin²∝
sin²∝=(1/3)²=1/9; cos²∝=1-1/9=8/9;
cos4∝=(cos²∝-sin²∝)²-4cos²∝*sin²∝=(8/9-1/9)²-4*(8/9)*(1/9)=49/81-32/81=17/81
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Verified answer
Ответ:
17/81
Объяснение:
cos4∝=cos²2∝-sin²2∝
cos2∝=cos²∝-sin²∝
sin2∝=2cos∝*sin∝
cos4∝=cos²2∝-sin²2∝=(cos²∝-sin²∝)²-4cos²∝*sin²∝
sin²∝=(1/3)²=1/9; cos²∝=1-1/9=8/9;
cos4∝=(cos²∝-sin²∝)²-4cos²∝*sin²∝=(8/9-1/9)²-4*(8/9)*(1/9)=49/81-32/81=17/81