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Неуловимыйтип
@Неуловимыйтип
August 2022
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Пусть f(x) = х2- Зх + 2. Задайте аналитически функции
у = f(-x); у = f(x + 2); у = /(3 - х); у = 4 - f(x)
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TARTILLO
Verified answer
Пусть f(x) = х2- Зх + 2.
Задайте аналитически функцииу1 = f(-x);
у1 = f(-x)=(- х)²- З(-х )+ 2 ⇒у1=(х)²+З(х )+ 2;
у = f(x + 2);
у2 = f(x + 2)=(x + 2)²- З(x + 2 )+ 2 ⇒у2=х²+4х +4-3x-6+ 2=х²+х ;
у2==х²+х
;
у = f(3 - х);
у3 = f(3-x)=(3-x )²- З(3-x )+ 2 ⇒у3=х²-6х +9-9+3x+ 2=х²-3
х+2;
у3=х²-3
х+2;
у = 4 - f(x)
у4= 4-(х²- Зх + 2)= 2-x²+3x;
у4=
2-x²+3x;
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Answers & Comments
Verified answer
Пусть f(x) = х2- Зх + 2.Задайте аналитически функцииу1 = f(-x);
у1 = f(-x)=(- х)²- З(-х )+ 2 ⇒у1=(х)²+З(х )+ 2;
у = f(x + 2);
у2 = f(x + 2)=(x + 2)²- З(x + 2 )+ 2 ⇒у2=х²+4х +4-3x-6+ 2=х²+х ;
у2==х²+х ;
у = f(3 - х);
у3 = f(3-x)=(3-x )²- З(3-x )+ 2 ⇒у3=х²-6х +9-9+3x+ 2=х²-3х+2;
у3=х²-3х+2;
у = 4 - f(x)
у4= 4-(х²- Зх + 2)= 2-x²+3x;
у4= 2-x²+3x;