[tex]\displaystyle\bf\\\Big|2-\frac{x}{5} \Big| > 3\\\\\\\left[\begin{array}{ccc}2-\dfrac{x}{5} > 3\\2-\dfrac{x}{5} < -3 \end{array}\right\\\\\\1)\\\\2-\frac{x}{5} > 3\\\\\\2\cdot 5-\frac{x}{5}\cdot 5 > 3\cdot 5\\\\\\10-x > 15\\\\-x > 5\\\\x < -5\\\\2)\\\\2-\frac{x}{5} < -3\\\\\\2\cdot 5-\frac{x}{5}\cdot 5 < -3\cdot 5\\\\\\10-x < -15\\\\-x < -25\\\\x > 25\\\\\\Otvet \ : \ x\in(-\infty \ , \ -5)\cup(25 \ ; \ +\infty)[/tex]