Помогите решить. 18^n+3/3^2n+5 × 2^n-2. Created by loveksana82. algebra-ru

3^2n+5 × 2^n-2...

loveksana82 @loveksana82

July 2022 1 6 Report

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18^n+3/3^2n+5 × 2^n-2

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$\frac{18^{n+3}}{3^{2n+5}*2^{n-2}}=\frac{(3^{2}*2)^{n+3}}{3^{2n+5}*2^{n-2}}=\frac{3^{2n+6}*2^{n+3}}{3^{2n+5}*2^{n-2}}=3^{2n+6-2n-5}*2^{n+3-n+2}=3*2^{5}=3*32=96\\\\Otvet:\boxed{96}$

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bassektrisy uglov a i d parallelograma abcd peresekayutsya v tochke lezhashej na sto

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