Срочно, ПОМОГИТЕ решить номер 1.. Created by loveksana82. algebra-ru

Срочно, ПОМОГИТЕ решить номер 1...

loveksana82 @loveksana82

July 2022 1 6 Report

Срочно, ПОМОГИТЕ решить номер 1.

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$\frac{x^{3}+3x^{2}-4x-12}{(x-2)(x+3)} =\frac{(x^{3}+3x^{2})-(4x+12)}{(x-2)(x+3)}=\frac{x^{2}(x+3)-4(x+3)}{(x-2)(x+3)}=\frac{(x+3)(x^{2}-4)}{(x-2)(x+3)}=\frac{(x+3)(x-2)(x+2)}{(x-2)(x+3)}=x+2\\\\Otvet:\boxed{x+2}$

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kaaitanskaya dochka glava priboj otvetit na voprosy 1 kakie kachestva geroj

pomogite pozhalujsta sostavit zadacha na nahozhdenie ploshadi treugolnika 8 kla

pomogite pozhalujsta8fbdfd41b5b6584e1531ec6ca12735c0 39426

bassektrisy uglov a i d parallelograma abcd peresekayutsya v tochke lezhashej na sto

bissektrisy uglov a i d parallelograma abcdperesekayutsya v tochke lezhashej na stor

pomogite reshit vyrazhenie 845 819

32n5 2n 2ae2d26bce0bee730bf7360fd641cc6ec 74523

pomogite reshit 5 nomer0c37434ad388e1922f12bd9420e82076 52592

pomogite pozhalujsta s 7 i 8 nomerom651903a5b5d8fb6efe5292882fe00ac8 9066

pomogite pozhalujsta s 6 nomerom573e17c2c214caab97942280d6112c2d 97753

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