Verified answer

[tex]\displaystyle\bf\\3x^{3}+8x^{2}+11x-27=x(3x^{2} +2x+10)-25\\\\\\3x^{3}+8x^{2}+11x-27=3x^{3} +2x^{2} +10x-25\\\\\\3x^{3}+8x^{2}+11x-27-3x^{3} -2x^{2} -10x+25=0\\\\\\6x^{2} +x-2=0\\\\D=1^{2} -4\cdot 6\cdot(-2)=1+48=49=7^{2} \\\\\\x_{1} =\frac{-1-7}{12} =-\frac{8}{12} =-\frac{2}{3} \\\\\\x_{2} =\frac{-1+7}{12}=\frac{6}{12} =\frac{1}{2} =0,5[/tex]

Ответ  :  выражения равны  при  x = - 2\3  и  x = 0,5