Verified answer

Ответ:

(a-1)(a^2-3a+1)

Объяснение:

[tex]a^3 - 4a^2 + 4a - 1 = (a^3 - 1) - (4a^2 - 4a)\\a^3 - 1 = (a-1)(a^2+a+1)\\4a^2-4a = 4a(a-1)\\\\(a^3-1) - (4a^2 - 4a) = (a-1)(a^2+a+1) - 4a(a-1) = (a-1)(a^2+a+1-4a) = (a-1)(a^2-3a+1)[/tex]