Відповідь:
4) (x ^ 2 - 7x + 5)/(x ^ 2 + 2x - 3) = 0
x = -(-7)+- v(-7)^2-4×1×5
x = 7+-v29/2
5)x/(x + 7) + (x + 7)/(x - 7) = (63-5x)/(x ^ 2 - 49)
x ^ 2 + 6x - 7 = 0
x = (- 6 +- v(6 ^ 2 - 4 * 1(- 7)/(2 * 1)
x = (- 6 +-8)/2
x = 1
x = - 7
6) (y ^ 2 - 2y) ^ 2 - 7(y^2 -2y) - 8 = 0
(- b+-v(b ^ 2 - 4(ac)/(2a)
a = 1, b = - 2 =-8B в
2+- v(- 2) ^ 2 - 4(1 * (- 8)
y = 1+-3
y = 4, - 2
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Відповідь:
4) (x ^ 2 - 7x + 5)/(x ^ 2 + 2x - 3) = 0
x = -(-7)+- v(-7)^2-4×1×5
x = 7+-v29/2
5)x/(x + 7) + (x + 7)/(x - 7) = (63-5x)/(x ^ 2 - 49)
x ^ 2 + 6x - 7 = 0
x = (- 6 +- v(6 ^ 2 - 4 * 1(- 7)/(2 * 1)
x = (- 6 +-8)/2
x = 1
x = - 7
6) (y ^ 2 - 2y) ^ 2 - 7(y^2 -2y) - 8 = 0
(- b+-v(b ^ 2 - 4(ac)/(2a)
a = 1, b = - 2 =-8B в
2+- v(- 2) ^ 2 - 4(1 * (- 8)
y = 1+-3
y = 4, - 2