Ответ:
[tex]\frac{16}{1-x^{16}}[/tex]
Объяснение:
1)[tex]\frac{1}{1-x}+\frac{1}{1+x}=\frac{1+x}{1-x^{2}} +\frac{1-x}{1-x^{2}}=\frac{2}{1-x^{2}}[/tex]
2)[tex]\frac{2}{1-x^{2}}+\frac{2}{1+x^{2}}=\frac{2+2x^{2}+2-2x^{2}}{1-x^{4}}=\frac{4}{1-x^{4}}[/tex]
3)[tex]\frac{4}{1-x^{4}}+\frac{4}{1+x^{4}}=\frac{8}{1-x^{8}}[/tex]
4)[tex]\frac{8}{1-x^{8}}+\frac{8}{1+x^{8}}=\frac{16}{1-x^{16}}[/tex]
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Answers & Comments
Ответ:
[tex]\frac{16}{1-x^{16}}[/tex]
Объяснение:
1)[tex]\frac{1}{1-x}+\frac{1}{1+x}=\frac{1+x}{1-x^{2}} +\frac{1-x}{1-x^{2}}=\frac{2}{1-x^{2}}[/tex]
2)[tex]\frac{2}{1-x^{2}}+\frac{2}{1+x^{2}}=\frac{2+2x^{2}+2-2x^{2}}{1-x^{4}}=\frac{4}{1-x^{4}}[/tex]
3)[tex]\frac{4}{1-x^{4}}+\frac{4}{1+x^{4}}=\frac{8}{1-x^{8}}[/tex]
4)[tex]\frac{8}{1-x^{8}}+\frac{8}{1+x^{8}}=\frac{16}{1-x^{16}}[/tex]