Ответ:
Объяснение: f(x)=2+Sin4x, ⇒ F(x) = 2x - (Cos4x)/4 +C. Если F(π/4)=3π, то получим: 3π= 2·π/4 - (Cosπ)/4 +C, ⇒ 3π = π/2 + 1/4 + C ⇒ C= 3π-π/2 -1/4 = 5π/2 - 1/4, ⇒ F(x) = 2x - (Cos4x)/4 +5π/2 - 1/4. Тогда F(7π/4)=2·7π/4 - (Cos7π)/4 +5π/2 - 1/4 = 7π/2 +1/4+ 5π/2 - 1/4 = 6π Отв: F(7π/4)=6π
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Ответ:
Объяснение: f(x)=2+Sin4x, ⇒ F(x) = 2x - (Cos4x)/4 +C. Если F(π/4)=3π, то получим: 3π= 2·π/4 - (Cosπ)/4 +C, ⇒ 3π = π/2 + 1/4 + C ⇒ C= 3π-π/2 -1/4 = 5π/2 - 1/4, ⇒ F(x) = 2x - (Cos4x)/4 +5π/2 - 1/4. Тогда F(7π/4)=2·7π/4 - (Cos7π)/4 +5π/2 - 1/4 = 7π/2 +1/4+ 5π/2 - 1/4 = 6π Отв: F(7π/4)=6π