4 )...

July 2022 1 8 Report

СРОЧНО РЕШИТЕ ЗАДАЧИ:

1. (cos (B-80°)-sinB*cos10°) / (cosB*cos10°)

2. ((cos (-3П/2) -sin 3П/2)^2) / (2sin П/6*tgП/4+cos(-П)-sinП/4 )

Answers & Comments

Sophie155 1.
$\frac{cos ( \beta -80к)-sin \beta *cos10к}{cos \beta *cos10к} = \frac{cos \beta*cos80к+sin \beta *sin80к-sin \beta *cos(90к-80к)}{cos \beta *cos10к} =$ $= \frac{cos \beta*cos80к+sin \beta *sin80к-sin \beta *sin80к}{cos \beta *cos10к}= \frac{cos \beta*cos80к}{cos \beta *cos10к}= \frac{cos80к}{cos10к}=$ $= \frac{cos(90к-10к)}{cos10к}= \frac{sin10к}{cos10к}=tg10к$

2.
$\frac{(cos(- \frac{3 \pi }{2})-sin \frac{3 \pi }{2})^2 }{2sin \frac{ \pi} {6} *tg \frac{ \pi} {4}+cos(- \pi )-sin \frac{ \pi} {4}}= \frac{(0-(-1))^2 }{2* \frac{ 1} {2} *1-1- \frac{ \sqrt{2} } {2}} = \frac{1}{- \frac{ \sqrt{2} }{2} } =- \frac{2}{ \sqrt{2} } =- \sqrt{2}$

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