(3x^3+2x^2+x)/(4x^2-49)>или равно 0. Решите неравенство.. Created by s201141181s. matematika-ru

(4x^2-49)>или равно 0. Решите неравенство...

s201141181s @s201141181s

July 2022 1 11 Report

(3x^3+2x^2+x)/(4x^2-49)>или равно 0. Решите неравенство.

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sedinalana

Verified answer

X(3x²+2x+1)/[(2x-7)(2x+7)]≥0
3x²+2x+1=0
D=4-12=-8<0 ⇒x∈R
x=0
2x-7=0⇒x=3,5
2x+7=0⇒x=-2,5
_ + _ +
------------(-3,5)----------[0]-------------------(3,5)--------------
x∈(-3,5;0] U (3,5;∞)

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