Найдите сумму корней уравнения (x^2-2x-3)lg((3x+5)/(4x+3))=0. Created by OliverRonnie. algebra-ru

(4x+3))=0...

July 2022 1 6 Report

Найдите сумму корней уравнения (x^2-2x-3)lg((3x+5)/(4x+3))=0

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aleks41 ОДЗ: 4х+3≠0, х≠-075; ((3х+5)/(4х+3)) >0: х∈(-∞; /5/3)∪(-3/4;∞).
х²-2х-3=0 или lg((3x+5)/(4x+3))=0.
х1=3; х2=-1. или (3х+5)/(4х+3)=1; 3х+5=4х+3: х3=2.
х1+х2+х3=3-1+2=4.
Ответ:4.

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