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ПолинаКурбатова
@ПолинаКурбатова
July 2022
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Найдите сумму первых n членов геометрической прогрессии 3/5; 3; 15;...;
N=4
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mikael2
Найдите сумму первых n членов геометрической прогрессии 3/5; 3; 15;...;
N=4
15/3=q=5 b1=3/5 s4=
b₁(1-qⁿ)/(1-q),=0.6(1-5
⁴
)/(1-5)=
=0.6*624/4=93.6
1 votes
Thanks 2
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Answers & Comments
N=4
15/3=q=5 b1=3/5 s4=b₁(1-qⁿ)/(1-q),=0.6(1-5⁴)/(1-5)=
=0.6*624/4=93.6