Помогите срочно решить: найдите y' (32), если у=x^-1/5 + x^1/5 +x. Created by fdu4er. algebra-ru

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August 2022 1 13 Report

Помогите срочно решить: найдите y' (32), если у=x^-1/5 + x^1/5 +x

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aleksandr1799 Y'(x) = - (x^(-6/5))/5 + (x^(-4/5)) / 5 + 1
y'(32) = - (32^(-6/5))/5 + (32^(-4/5)) / 5 + 1 = -1/(64*5) + 1/(16*5) + 1 = (-1+4+320)/320 = 323/320

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