Cм. рисунок.
α+β=π
tgα=6/5
ctgα=5/6
tgβ=tg(π-α)=-tgα=-6/5
ctgβ=-5/6
По формуле:
1+tg²α=1/cos²α
cos²α=25/61
1+ctg²α=1/sin²α
sin²α=36/61
cos²β=sin²α=36/61
sin²β=cos²α=25/61
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Verified answer
Cм. рисунок.
α+β=π
tgα=6/5
ctgα=5/6
tgβ=tg(π-α)=-tgα=-6/5
ctgβ=-5/6
По формуле:
1+tg²α=1/cos²α
cos²α=25/61
1+ctg²α=1/sin²α
sin²α=36/61
cos²β=sin²α=36/61
sin²β=cos²α=25/61