Verified answer

[tex]\displaystyle\bf\\y=Sin(5x^{2} +4x+3)\\\\\\y'=\Big[Sin(5x^{2} +4x+3)\Big]'=Cos(5x^{2} +4x+3)\cdot(5x^{2} +4x+3)'=\\\\\\=Cos(5x^{2} +4x+3)\cdot (10x+4)[/tex]

Відповідь:

Формула: (f(u(x)))' = fu'(u)*uₓ'(x)

y = sin(5x²+4x+3)

y' = (sin(5x²+4x+3))' = (sin(5x²+4x+3))'*(5x²+4x+3)' = cos(5x²+4x+3)*(5*2x+4) =

cos(5x²+4x+3)*(10x+4)