Ответ:
98,01
Объяснение:
[tex]cos\beta =\sqrt{1-sin^2\beta}=\sqrt{1-0,01}=\sqrt{0,99}\\ctg\beta=\frac{\sqrt{0,99}}{0,1}\\ ctg^2\beta-cos^2\beta=(\frac{\sqrt{0,99}}{0,1})^2-(\sqrt{0,99})^2=\frac{0,99}{0,01}-0,99=99-0,99=98,01\\[/tex]
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Answers & Comments
Ответ:
98,01
Объяснение:
[tex]cos\beta =\sqrt{1-sin^2\beta}=\sqrt{1-0,01}=\sqrt{0,99}\\ctg\beta=\frac{\sqrt{0,99}}{0,1}\\ ctg^2\beta-cos^2\beta=(\frac{\sqrt{0,99}}{0,1})^2-(\sqrt{0,99})^2=\frac{0,99}{0,01}-0,99=99-0,99=98,01\\[/tex]