Помогите решить пример! 4∛5 - ∛625 - ∛5/64. Created by undeadarmy. algebra-ru

64...

LFP

Verified answer

∛625 = ∛(5^4) = 5∛5
∛(5/64) = ∛5 / ∛64 = ∛5 / 4 = 0.25∛5
(4 - 5 - 0.25) * ∛5 = -1.25 * ∛5

0 votes Thanks 0

volkodav575

Verified answer

$4 \sqrt[3]{5}-\sqrt[3]{625}-\sqrt[3]{ \frac{5}{64} }= 4 \sqrt[3]{5}-\sqrt[3]{125*5}- \sqrt[3]{ 5*\frac{1}{64} }= \\ =4 \sqrt[3]{5}-5\sqrt[3]{5}- \frac{1}{4} \sqrt[3]{ 5}=\sqrt[3]{5}(4 -5- \frac{1}{4})=-1\frac{1}{4}\sqrt[3]{5}$

0 votes Thanks 1

undeadarmy А почему перед дробью четыре в начале?

volkodav575 Описка)\

undeadarmy Спасибо большое!

Answers & Comments

Verified answer

Verified answer

evgenij onegin chem interesna derevnya v kotoroj okazalsya gerojrazvernutyj otve

v okruzhnosti cherez seredinu o hordy bd provedena horda ac tak chto dugi ab i cd

6) = cosx...

pomogite ochen nuzhno tolko nuzhno vse podrobno dokazyvatv kruge provede

evgenij onegin chem interesna derevnya v kotoroj okazalsya geroj

sovershit cepochku prevrashenijfe fecl feoh feo feso

zapisat tri uravneniya reakcii v hode kotoryh poluchitsya feno

najdite radius okruzhnosti vpisannoj v pravilnyj treugolnik so storonoj koren

рекомендуемые вопросы

Helpful Links

Helpful Social