Ответ:
Применяем формулу [tex]\displaystyle \int \frac{dx}{\sqrt{kx+b}}=\frac{1}{k}\cdot 2\sqrt{kx+b}+C[/tex] .
[tex]\displaystyle \int \Big(\frac{10}{\sqrt{5+2x}}-3x^{-11}\Big)\, dx=10\int \frac{dx}{\sqrt{5+2x}}-3\int x^{-11}\, dx=\\\\\\=10\cdot \frac{1}{2}\cdot 2\sqrt{5+2x}-3\cdot \frac{x^{-10}}{-10}+C=10\cdot \sqrt{5+2x}+\frac{3}{10\cdot x^{10}}+C[/tex]
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Ответ:
Применяем формулу [tex]\displaystyle \int \frac{dx}{\sqrt{kx+b}}=\frac{1}{k}\cdot 2\sqrt{kx+b}+C[/tex] .
[tex]\displaystyle \int \Big(\frac{10}{\sqrt{5+2x}}-3x^{-11}\Big)\, dx=10\int \frac{dx}{\sqrt{5+2x}}-3\int x^{-11}\, dx=\\\\\\=10\cdot \frac{1}{2}\cdot 2\sqrt{5+2x}-3\cdot \frac{x^{-10}}{-10}+C=10\cdot \sqrt{5+2x}+\frac{3}{10\cdot x^{10}}+C[/tex]