Объяснение:
по формулам привидения:
1).
[tex]cos {135}^{0} = cos( {90}^{0} + {45}^{0} ) = - sin {45}^{0} = - \frac{ \sqrt{2} }{2} [/tex]
2).
[tex]sin \frac{8\pi}{3} = sin( \frac{9\pi}{3} - \frac{1\pi}{3} ) = sin(3\pi - \frac{\pi}{3} ) = sin \frac{\pi}{3} = \frac{ \sqrt{3} }{2} [/tex]
3).
[tex]tg \frac{7\pi}{3} = tg( \frac{6\pi}{3} + \frac{\pi}{3}) = tg(2\pi + \frac{\pi}{3} ) = tg \frac{\pi}{3} = \sqrt{3} [/tex]
4).
формула косинус двойного аргумента:
[tex]cos2 \alpha = {cos}^{2} \alpha - {sin}^{2} \alpha [/tex]
[tex] {cos}^{2} \frac{\pi}{8} - {sin}^{2} \frac{\pi}{8} = \\ = cos(2 \times \frac{\pi}{8} ) = \\ = cos \frac{\pi}{4} = \frac{ \sqrt{2} }{2} [/tex]
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Answers & Comments
Объяснение:
по формулам привидения:
1).
[tex]cos {135}^{0} = cos( {90}^{0} + {45}^{0} ) = - sin {45}^{0} = - \frac{ \sqrt{2} }{2} [/tex]
2).
[tex]sin \frac{8\pi}{3} = sin( \frac{9\pi}{3} - \frac{1\pi}{3} ) = sin(3\pi - \frac{\pi}{3} ) = sin \frac{\pi}{3} = \frac{ \sqrt{3} }{2} [/tex]
3).
[tex]tg \frac{7\pi}{3} = tg( \frac{6\pi}{3} + \frac{\pi}{3}) = tg(2\pi + \frac{\pi}{3} ) = tg \frac{\pi}{3} = \sqrt{3} [/tex]
4).
формула косинус двойного аргумента:
[tex]cos2 \alpha = {cos}^{2} \alpha - {sin}^{2} \alpha [/tex]
[tex] {cos}^{2} \frac{\pi}{8} - {sin}^{2} \frac{\pi}{8} = \\ = cos(2 \times \frac{\pi}{8} ) = \\ = cos \frac{\pi}{4} = \frac{ \sqrt{2} }{2} [/tex]