Ответ:
1)
(sin(π/2+a)-cos(π+a))/sin(2π-a)
(cos(a)+cos(a))/-sin(a)
-2ctg(a)
2)
cos(30°)*cos(15°)-sin(30°)*sin(15°)
cos(30°+15°)=cos(45°)=√(2)/2
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Answers & Comments
Ответ:
1)
(sin(π/2+a)-cos(π+a))/sin(2π-a)
(cos(a)+cos(a))/-sin(a)
-2ctg(a)
2)
cos(30°)*cos(15°)-sin(30°)*sin(15°)
cos(30°+15°)=cos(45°)=√(2)/2