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Ответ:

[tex](6; -2)[/tex]

Объяснение:

[tex]\displaystyle \left \{ {{\dfrac{x}{3}+\dfrac{y}{2}=1} \atop {y+x=4}} \right. \Leftrightarrow \left \{ {{2x+3y=6} \atop {x+y=4}} \right. \Leftrightarrow \left \{ {{2x+3y=6} \atop {-3x-3y=-12}} \right. \bigg |+[/tex]

[tex]2x-3x+3y-3y=6-12;[/tex]

[tex]-x=-6;[/tex]

[tex]x=6;[/tex]

[tex]y=4-x \Rightarrow y=4-6=-2; \quad (6; -2);[/tex]