первая 2x-y+1=0
вторая 2x-y+5=0
d=|C1-C2|/√(A^2+B^2)=|1-5|/√(2^2+(-1)^2)=4/√5
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первая 2x-y+1=0
вторая 2x-y+5=0
d=|C1-C2|/√(A^2+B^2)=|1-5|/√(2^2+(-1)^2)=4/√5