Ответ:
Дано : ΔABC; ∠A=60°; ∠B=45°; AC=√6 см
Найти : a = CB - ?
По теореме синусов
�
sin
=
⋅
6
0
4
5
3
2
:
sinB
AC
sinA
a
a=
AC⋅sinA
sin45
o
⋅sin60
=3
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Ответ:
Дано : ΔABC; ∠A=60°; ∠B=45°; AC=√6 см
Найти : a = CB - ?
По теореме синусов
�
�
sin
�
=
�
sin
�
�
=
�
�
⋅
sin
�
sin
�
=
6
⋅
sin
6
0
�
sin
4
5
�
=
=
6
⋅
3
2
:
2
2
=
6
⋅
3
2
⋅
2
2
=
3
sinB
AC
=
sinA
a
a=
sinB
AC⋅sinA
=
sin45
o
6
⋅sin60
o
=
=
6
⋅
2
3
:
2
2
=
6
⋅
2
3
⋅
2
2
=3