Освобождения от иррациональности в знаменателе дроби
1) ( √x+√y)/(√x-√y)
2) (20-4√a)/(5√a-a)
3) (9√a+√b)/(9b+81√ab)
4) (x-a√x)/(√ax-a√a)
1) (√x+√y)/(√x-√y)=
= (√x+√y)²/[(√x-√y)·( √x+√y)] =
= (√x+√y)²/[(√x)²-(√y)²] =
= (√x+√y)²/(x-y)
2) (20-4√a)/(5√a-a) =
= 4(5 - √a)/(5√а - √a·√a)
= 4(5 - √a)/[√a(5 -√a)] =
= 4/√a =
= 4√a/(√a·√a) =
= 4√a/a
3) (9√a+√b)/(9b+81√ab) =
= (9√a+√b)/[9√b(√b+9√a]) =
= 1/(9√b) =
= √b/(9b)
4) (x-a√x)/(√ax-a√a) =
= √x(√x - a)/[√a(√x - a)] =
= √x/√a =
= √(ax)/a
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Answers & Comments
1) (√x+√y)/(√x-√y)=
= (√x+√y)²/[(√x-√y)·( √x+√y)] =
= (√x+√y)²/[(√x)²-(√y)²] =
= (√x+√y)²/(x-y)
2) (20-4√a)/(5√a-a) =
= 4(5 - √a)/(5√а - √a·√a)
= 4(5 - √a)/[√a(5 -√a)] =
= 4/√a =
= 4√a/(√a·√a) =
= 4√a/a
3) (9√a+√b)/(9b+81√ab) =
= (9√a+√b)/[9√b(√b+9√a]) =
= 1/(9√b) =
= √b/(9b)
4) (x-a√x)/(√ax-a√a) =
= √x(√x - a)/[√a(√x - a)] =
= √x/√a =
= √(ax)/a