[tex]\displaystyle\bf\\\frac{Sin117^\circ+3Cos153^\circ+Sin720^\circ}{Cos27^\circ}= \\\\\\=\frac{Sin(90^\circ+27^\circ)+3Cos(180-27^\circ)^\circ+Sin(2\cdot 360^\circ)}{Cos27^\circ}=\\\\\\=\frac{Cos27^\circ-3Cos27^\circ+0}{Cos27^\circ}= \frac{-2Cos27^\circ}{Cos27^\circ} =-2[/tex]