Verified answer

7)=0+1+0=1

8)=6*1+4*0+4*3/4=6+3=9

Ответ:

7)1;

8)9;

Объяснение:

7) cos(3π/2)-sin(3π/2)+ctg(3π/2)=

=cos(π+π/2)-sin(π+π/2)+ctg(π+π/2)=

=-cos(π/2)+sin(π/2)+ctg(π/2)=

=-0+1+0=1

8)6cos(0)+4sin(2π)+4sin^2(2π/3)=

=6*1+4*0+4*(√(3)/2)^2=

=6+0+4*3/4=6+3=9