July 2022 0 47 Report
Чевианы AA1, BB1, CC1 треугольника ABC пересекаются в точке P. Известно, что AC1:C1B=2:3, BP:PB1=3:1. Найдите следующие отношения.

AC1:C1B=
AP:PA1=
BP:PB1=
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