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July 2022
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cos(2x)+cos^2(x)=0
Решите уравнение
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MrSoys
Cos2x=cos²x-sin²x
cos²x-sin²x+cos²x=0
2cos²x-sin²x=0
Делим на cos²x
2-tg²x=0
tg²x=2
x=arctg
+πn, n∈Z или x=-arctg
+πm, m∈Z
2 votes
Thanks 1
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Answers & Comments
cos²x-sin²x+cos²x=0
2cos²x-sin²x=0
Делим на cos²x
2-tg²x=0
tg²x=2
x=arctg+πn, n∈Z или x=-arctg+πm, m∈Z