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August 2022
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sin(2x)-2cos(x)=0
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lesnikjocker
2sin x* cos x - 2 cosx = 0
2 cos x(sin x -1) =0
1)2cosx =0
cosx=0
x=П/2+ Пn, где n є Z
2)sinx-1=0
sin x = 1
x=П/2 + 2Пm, где m є Z
2 votes
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Answers & Comments
2 cos x(sin x -1) =0
1)2cosx =0
cosx=0
x=П/2+ Пn, где n є Z
2)sinx-1=0
sin x = 1
x=П/2 + 2Пm, где m є Z