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@20000328
July 2022
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cos2x+cosx+1=0, 54 балла
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andreevnaelina
Cos2x+cosx+1=0
2соsx² -1 +cosx+1=0
cosx*(2cosx+1)=0
2соsx+1=0 или cosx=0
х= 2п/3+2кп, к€Z или п/2+кп, к€Z
x=4п/3+2кп, к€Z
Ответ: п/2+кп, к€Z;
х= 2п/3+2кп, к€Z;
x=4п/3+2кп, к€Z
2 votes
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Answers & Comments
2соsx² -1 +cosx+1=0
cosx*(2cosx+1)=0
2соsx+1=0 или cosx=0
х= 2п/3+2кп, к€Z или п/2+кп, к€Z
x=4п/3+2кп, к€Z
Ответ: п/2+кп, к€Z;
х= 2п/3+2кп, к€Z;
x=4п/3+2кп, к€Z