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batalygina
@batalygina
July 2022
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cos3x*cos6x=cosx*cos4x
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7NoD7
Cosacosb=1/2[cos(a-b)+cos(a+b)]
Cos3xcos6x=1/2[cos3x+cos9x]
Cosxcos4x=1/2[cos3x+cos5x]
Cos9x-cos5x=0
-2sin((9x+5x)/2)sin((9x-5x)/2)=0
Sin7xsin2x=0
Sin7x=0
7x=pk
X=pk/7
Sin2x=0
2x=pk
X=pk/2
1 votes
Thanks 3
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Answers & Comments
Cos3xcos6x=1/2[cos3x+cos9x]
Cosxcos4x=1/2[cos3x+cos5x]
Cos9x-cos5x=0
-2sin((9x+5x)/2)sin((9x-5x)/2)=0
Sin7xsin2x=0
Sin7x=0
7x=pk
X=pk/7
Sin2x=0
2x=pk
X=pk/2