Дано f(x)=2x2-3x .Решите уравнение f(sin x )=0. Created by lil5. algebra-ru

Дано f(x)=2x2-3x .Решите уравнение f(sin x )=0...

lil5 @lil5

July 2022 1 9 Report

Дано f(x)=2x2-3x .Решите уравнение f(sin x )=0

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$f(x)=2x^2-3x\; \; \; \to \; \; f(sinx)=2sin^2x-3sinx=0\\\\sinx(2sinx-3)=0\\\\1)sinx=0\; ,\; \; x=\pi n,\; n\in Z\\\\2sinx-3=0\; ,\; \; sinx=\frac{3}{2}>1\; \; \to \; \; net\; \; reshenij,tak\; kak\; |sinx| \leq 1$

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