Ответ: -50

Объяснение:

22.

[tex]\frac{a+3}{a^2-10+25} *\frac{2a-10}{a^2-9}-\frac{1}{a-5}= \frac{(a+3)*2(a-5)}{(a-5)^2*(a-3)*(a+3)} -\frac{1}{a-5} =\\[/tex]

[tex]=\frac{2}{(a-5)(a-3)} -\frac{1}{a-5}= \frac{2}{(a-5)(a-3)} - \frac{(a-3)}{(a-5)(a-3)}= \frac{2-a+3}{(a-5)(a-3)} = \frac{5-a}{(a-5)(a-3)}= \\[/tex]

[tex]=\frac{a-5}{(a-5)(3-a)} = \frac{1}{3-a}[/tex]

a=3.02 => [tex]\frac{1}{3-3.02} = \frac{1}{-0.02} =[/tex]-50