докажите равенство
tg²a-sin²a=tg²a*sin²a
срочно плиииииз
tg^2a-sin^2a=tg^2a*sin^2a
sin^2a/cos^2a-sin^2a=sin^2a/cos^2a*sin^2a
(sin^2a-sin^2a*cos^2a)/cos^2a=sin^4a/cos^2a
(sin^2a(1-cos^2a))/cos^2a=sin^4a/cos^2a
(sin^2a*sin^2a)/cos^2a=sin^4a/cos^2a
sin^4a/cos^2a=sin^4a/cos^2a
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Answers & Comments
tg^2a-sin^2a=tg^2a*sin^2a
sin^2a/cos^2a-sin^2a=sin^2a/cos^2a*sin^2a
(sin^2a-sin^2a*cos^2a)/cos^2a=sin^4a/cos^2a
(sin^2a(1-cos^2a))/cos^2a=sin^4a/cos^2a
(sin^2a*sin^2a)/cos^2a=sin^4a/cos^2a
sin^4a/cos^2a=sin^4a/cos^2a