Ответ:

H2SO4 (aq) + H2S (g) → SO2 (aq) + 2 H2O (l) + S (s)

This is an oxidation-reduction (redox) reaction:

S-II - 2 e- → S0 (oxidation)

S-II - 6 e- → SIV (oxidation)

SVI + 6 e- → S0 (reduction)

SVI + 2 e- → SIV (reduction)

H2S is a reducing agent, H2S is a reducing agent, H2SO4 is an oxidizing agent, H2SO4 is an oxidizing agent.

Reactants:

accessed: 2019-09-07

Объяснение: