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Решение смотри на фотографии

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DimaPuchkov Замена $t = \sin{x}; \ \ dt= \cos{x} \, dx \ \Rightarrow \ dx = \frac{dt}{\cos{x}} \\ \\ \int {\frac{\cos{x}}{ \sqrt[3]{t+2} } \cdot \frac{dt}{\cos{x}}}=\int \frac{dt}{ \sqrt[3]{t+2} }= \int \frac{d(t+2)}{\sqrt[3]{t+2}}=\frac{(t+2)^{\frac{2}{3}}}{\frac{2}{3}} +C =\\ \\ = \frac{3}{2} \cdot \sqrt[3]{(t+2)^2} + C= \frac{3}{2} \cdot \sqrt[3]{(\sin{x}+2)^2} + C$

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08e6262dc9c1865f85ea569becf7ed8c

1 2 3 64b680cd307ab

bd1cfa560ea8d3bf4201d287e488675d

vi ii 64afbe65f0afb

1 2 3 4 64abe4bbc9156

1 2 3 4 64a9f1c9b84fa

ed7553109b051819d37f06608bb610ab

1 2 ii 64a626991420a

tex]

1 a xy b b xy a 2b ta b 64a352121ddb9

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