Ответ:
(-∞;3]∪[4,5;7]
Объяснение:
(3x-6)(x+2)²(7-x)(x-4,5)≥0
2(x-3)(x+2)²(7-x)(x-4,5)≥0
x=3, x=-2, x=7, x=4,5 - нули функции
+ + - + -
//////// -2//////////////3_________4,5////////////7_______
x∈(-∞; 3]∪[4,5; 7]
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Ответ:
(-∞;3]∪[4,5;7]
Объяснение:
(3x-6)(x+2)²(7-x)(x-4,5)≥0
2(x-3)(x+2)²(7-x)(x-4,5)≥0
x=3, x=-2, x=7, x=4,5 - нули функции
+ + - + -
//////// -2//////////////3_________4,5////////////7_______
x∈(-∞; 3]∪[4,5; 7]