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shogunuz
@shogunuz
July 2022
1
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Мощность двигателя подъемного крана 5000Вт. Кран поднимает груз массой 800кг на высоту 10м за 20с. опредилите КПД крана.
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yellok
N=5000
Вт
m=
800кг
h=
10м
t=
20с
КПД =?
КПД=
%=
%= 0.8*100%=80%
4 votes
Thanks 6
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Answers & Comments
m=800кг
h=10м
t= 20с
КПД =?
КПД=%=%= 0.8*100%=80%