Home
О нас
Products
Services
Регистрация
Войти
Поиск
mrhunter913
@mrhunter913
July 2022
1
28
Report
Найдите координаты центра и радиус сферы, заданной уравнением: а) x^2+y^2+z^2=49:
b) (x-3)^2+(y+2)^2+z^2=2
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
dmaxim4ik
Verified answer
1.
x^2+y^2+z^2=49
Радиус =√49=7 Центр (0,0,0)
2. (x-3)^2+(y+2)^2+z^2=2
Радиус =√2 Центр (3,-2,0)
6 votes
Thanks 16
×
Report "Найдите координаты центра и радиус сферы, заданной уравнением: а) x^2+y^2+z^2=49..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
1. x^2+y^2+z^2=49Радиус =√49=7 Центр (0,0,0)
2. (x-3)^2+(y+2)^2+z^2=2
Радиус =√2 Центр (3,-2,0)