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zar88
@zar88
July 2022
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Найдите наибольшее и наименьшее значения функции f(x) = xв кубе – 3x на отрезках [-0,5; 0,5] и [-1,5; 2]. Помогите пожалуйста очень надо
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sedinalana
Verified answer
F`(x)=3x²-3=3(x-1)(x+1)=0
x=1 x=-1
1)x=1∉[-0,5;0,5] x=-1∉[-0,5;0,5]
f(-0,5)=-0,125+1,5=1,375 наиб
f(0,5)=0,125-1,5=-1,375 наим
2)x=1∈[-1,5;2] x=-1∈[-1,5;2]
f(-1,5)=-3,375+4,5=1,125
f(-1)=-1+3=2 наиб
f(1)=1-3=-2 наим
f(2)=8-6=2 наиб
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Answers & Comments
Verified answer
F`(x)=3x²-3=3(x-1)(x+1)=0x=1 x=-1
1)x=1∉[-0,5;0,5] x=-1∉[-0,5;0,5]
f(-0,5)=-0,125+1,5=1,375 наиб
f(0,5)=0,125-1,5=-1,375 наим
2)x=1∈[-1,5;2] x=-1∈[-1,5;2]
f(-1,5)=-3,375+4,5=1,125
f(-1)=-1+3=2 наиб
f(1)=1-3=-2 наим
f(2)=8-6=2 наиб